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Proof step 15 from proof same-subclasses-trans (previous step)

same-subclasses(class, str0, str1), (∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0)) ∧ (∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0)) ⊦ (class∃(str1, class0) ∧ class0 ≤ class → class∃(str, class0)) ∧ (interface∃(str1, class1) ∧ class1 ≤ class → interface∃(str, class1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
same-subclasses(class, str0, str1), ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ (class∃(str1, class0) ∧ class0 ≤ class → class∃(str, class0)) ∧ (interface∃(str1, class1) ∧ class1 ≤ class → interface∃(str, class1))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]