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Proof step 5 from proof same-subclasses-trans (previous step)

class0 ≤ class, class∃(str1, class0), class∃(str1, class0) ∧ class0 ≤ class → class∃(str0, class0), ∀ class0. interface∃(str1, class0) ∧ class0 ≤ class → interface∃(str0, class0), ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ class∃(str, class0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
class0 ≤ class, class∃(str1, class0), class∃(str0, class0), ∀ class0. interface∃(str1, class0) ∧ class0 ≤ class → interface∃(str0, class0), ∀ class0. interface∃(str0, class0) ∧ class0 ≤ class → interface∃(str, class0), ∀ class0. class∃(str0, class0) ∧ class0 ≤ class → class∃(str, class0) ⊦ class∃(str, class0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]