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Proof step 56 from proof validfieldinits-def-01 (previous step)

fv = sk0 × val, ∀ str, st. validfieldinits(str, fis0, st) ↔ validfieldinits(fis0, st) ∧ ¬ junkrefs(str, fis0 .vals, st) ∧ (∀ sk. sk ∈ fis0 → type∃(str, sk .fs .type)) ⊦ validfieldinits(str, fv ' + fis0, st) ↔ validfieldinits(fv ' + fis0, st) ∧ ¬ junkrefs(str, val ' + fis0 .vals, st) ∧ (∀ sk. sk ∈ fv ' + fis0 → type∃(str, sk .fs .type))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 55:
∀ str, st. validfieldinits(str, fis0, st) ↔ validfieldinits(fis0, st) ∧ ¬ junkrefs(str, fis0 .vals, st) ∧ (∀ sk. sk ∈ fis0 → type∃(str, sk .fs .type)) ⊦ validfieldinits(str, (sk0 × val) ' + fis0, st) ↔ validfieldinits((sk0 × val) ' + fis0, st) ∧ ¬ junkrefs(str, val ' + fis0 .vals, st) ∧ (∀ sk. sk ∈ (sk0 × val) ' + fis0 → type∃(str, sk .fs .type))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]