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Proof step 3 from proof validfieldinits-junkref (previous step)

fis[sk] = refval(r), validfieldinits(fis, st), junkref(str, r, st), sk ∈ fis, ∀ sk. sk ∈ fis → type∃(str, sk .fs .type) ⊦ refval(r) ∈ fis .vals ∧ junkref(str, r, st)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : okfuns, , vals-at-in-01, ⊦ sk ∈ fis ∧ fis[sk] = val → val ∈ fis .vals])]]