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Proof step 6 from proof validfieldinits-junkref (previous step)

fis[sk] = refval(r), sk ∈ fis, junkref(str, r, st), validfieldinits(fis, st) ∧ ¬ junkrefs(str, fis .vals, st) ∧ (∀ sk. sk ∈ fis → type∃(str, sk .fs .type)) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
fis[sk] = refval(r), validfieldinits(fis, st), junkref(str, r, st), sk ∈ fis, ∀ sk. sk ∈ fis → type∃(str, sk .fs .type) ⊦ junkrefs(str, fis .vals, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]