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Proof step 8 from proof validfieldinits-junkref (conclusion)

⊦ junkref(str, r, st) ∧ fis[sk] = refval(r) ∧ sk ∈ fis → ¬ validfieldinits(str, fis, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
fis[sk] = refval(r), sk ∈ fis, junkref(str, r, st), validfieldinits(str, fis, st) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]