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Proof step 2 from proof validfieldinits-one (previous step)

∀ sk0, val0. sk0 × val0 = sk × val → is_fskey(sk0) ∧ type∃(str, sk0 .fs .type) ∧ validval(str, val0, sk0 .fs .type, st), sk .fs = mkfs(class, ty, fieldvar) ⊦ ¬ is_indexkey(sk) ∧ type∃(str, ty) ∧ validval(str, val, ty, st)

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (sk, val)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_indexkey(sk) → ¬ is_fskey(sk)], [CSIMPSEQ : ⊦ ¬ is_indexkey(sk) ↔ is_fskey(sk)], [CSIMPSEQ : ⊦ mkfs(class, ty, fieldvar) .type = ty])], [EXTRATERMS : (sk, val)]]