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Proof step 8 from proof validfieldinits-one (previous step)

⊦ validfieldinits(str, fv ', st) ↔ ¬ is_indexkey(fv .1) ∧ type∃(str, fv .1 .fs .type) ∧ validval(str, fv .2, fv .1 .fs .type, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
fv = sk × val ⊦ validfieldinits(str, fv ', st) ↔ ¬ is_indexkey(sk) ∧ type∃(str, sk .fs .type) ∧ validval(str, val, sk .fs .type, st)

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]