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Proof step 24 from proof validfieldinits-rec (previous step)

fv = sk × val ⊦ validfieldinits(str, fv ' + fis, st) ↔ ¬ is_indexkey(sk) ∧ validval(str, val, sk .fs .type, st) ∧ type∃(str, sk .fs .type) ∧ validfieldinits(str, fis, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
⊦ validfieldinits(str, (sk × val) ' + fis, st) ↔ ¬ is_indexkey(sk) ∧ validval(str, val, sk .fs .type, st) ∧ type∃(str, sk .fs .type) ∧ validfieldinits(str, fis, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]