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Proof step 9 from proof validref-put-field-refval-01 (conclusion)

⊦ is_referencevalue(val) ∧ is_fskey(sk) ∧ validref(str, val .refval, sk .fs .type, st) ∧ validref(str, r, ty, st) ∧ is_reftype(sk .fs .type) → validref(str, r, ty, st[r0 -- sk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
is_reftype(sk .fs .type), validref(str, r, ty, st), validref(str, val .refval, sk .fs .type, st), is_fskey(sk), is_referencevalue(val) ⊦ validref(str, r, ty, st[r0 -- sk, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]