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Proof step 15 from proof validref-put-norefval-equiv (previous step)

sk = fs ', okval(st[r1 -- sk], fs .type), r1 -- sk ∈ st, is_fskey(sk), okval(val, fs .type), r1 ∈ st ⊦ validref(str, r, ty, st[r1 -- sk, val]) ↔ validref(str, r, ty, st), sk = _length, fs .type = void_type, is_referencevalue(val)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
okval(st[r1 -- fs '], fs .type), r1 -- fs ' ∈ st, okval(val, fs .type), r1 ∈ st ⊦ validref(str, r, ty, st[r1 -- fs ', val]) ↔ validref(str, r, ty, st), fs ' = _length, fs .type = void_type, is_referencevalue(val)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_fskey(fs ')])]]