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Proof step 17 from proof validref-put-norefval-equiv (conclusion)

⊦ okval(st[r1 -- sk], sk .fs .type) ∧ r1 -- sk ∈ st ∧ ¬ is_referencevalue(val) ∧ is_fskey(sk) ∧ okval(val, sk .fs .type) ∧ sk .fs .type ≠ void_type ∧ sk ≠ _length → (validref(str, r, ty, st[r1 -- sk, val]) ↔ validref(str, r, ty, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
okval(st[r1 -- sk], sk .fs .type), r1 -- sk ∈ st, is_fskey(sk), okval(val, sk .fs .type), r1 ∈ st ⊦ validref(str, r, ty, st[r1 -- sk, val]) ↔ validref(str, r, ty, st), sk = _length, sk .fs .type = void_type, is_referencevalue(val)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]