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Proof step 15 from proof validref-putrkvs-norefval (conclusion)

⊦ ¬ is_referencevalue(val) ∧ okval(st[r1 -- sk], sk .fs .type) ∧ r1 -- sk ∈ st ∧ is_fskey(sk) ∧ okval(val, sk .fs .type) ∧ sk .fs .type ≠ void_type ∧ sk ≠ _length → (validref(str, r, ty, st[((r1 -- sk) × val) ' + rkvs]) ↔ validref(str, r, ty, st[rkvs]))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
okval(st[r1 -- sk], sk .fs .type), r1 -- sk ∈ st, is_fskey(sk), okval(val, sk .fs .type), r1 ∈ st ⊦ validref(str, r, ty, st[((r1 -- sk) × val) ' + rkvs]) ↔ validref(str, r, ty, st[rkvs]), sk = _length, sk .fs .type = void_type, is_referencevalue(val)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]