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Proof step 13 from proof validref-subset-01 (previous step)

st ⊆ st0 ⊦ validref(str, r, ty, st0) ↔ validref(str, r, ty, st), junkref(str, r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: validref-subset , F , [str, r, ty, st, st1] → [str, r, ty, st, st0] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (str, r, ty, st, st0)]]