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Proof step 5 from proof validrefkeynotnull-addobj (previous step)

validrefvalnotnull(str, st[rk], ty1, st), rk ∈ st, newref(r1, st) ⊦ r1 = jvmref, rk ∈ addobj(r1, class, fis, st) ∧ validrefvalnotnull(str, addobj(r1, class, fis, st)[rk], ty1, addobj(r1, class, fis, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
validrefvalnotnull(str, st[rk], ty1, st), rk ∈ st, newref(r1, st) ⊦ r1 = jvmref, validrefvalnotnull(str, addobj(r1, class, fis, st)[rk], ty1, addobj(r1, class, fis, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st → rk ∈ addobj(r, class1, fis, st)])]]