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Proof step 21 from proof validrefkeynotnull-subset (previous step)

st[rk] = refval(r), r = jvmref ∨ st[r -- _type] .type ≤ ty ∧ ¬ junkref(str, r, st), rk ∈ st, st ⊆ st1, rk ∈ st1 ⊦ r = jvmref, is_referencevalue(st1[rk]) ∧ st1[rk] .refval ≠ jvmref ∧ validref(str, st1[rk] .refval, ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
st[rk] = refval(r), rk ∈ st, st ⊆ st1, rk ∈ st1, st[r -- _type] .type ≤ ty ⊦ r = jvmref, junkref(str, r, st), is_referencevalue(st1[rk]) ∧ st1[rk] .refval ≠ jvmref ∧ validref(str, st1[rk] .refval, ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]