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Proof step 27 from proof validrefkeynotnull-subset (previous step)

st[rk] = refval(r), is_referencevalue(st[rk]), validrefnotnull(str, r, ty, st), rk ∈ st, st ⊆ st1, rk ∈ st1 ⊦ r = jvmref, validrefvalnotnull(str, st1[rk], ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ validrefnotnull(str, r, ty, st) → r ≠ jvmref
Proof step 26:
st[rk] = refval(r), rk ∈ st1, st ⊆ st1, rk ∈ st, validrefnotnull(str, r, ty, st) ⊦ r = jvmref, validrefvalnotnull(str, st1[rk], ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]