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Proof step 29 from proof validrefkeynotnull-subset (previous step)

is_referencevalue(st[rk]) ∧ validrefnotnull(str, st[rk] .refval, ty, st), rk ∈ st, st ⊆ st1 ⊦ rk ∈ st1 ∧ validrefvalnotnull(str, st1[rk], ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ validrefnotnull(str, r, ty, st) → r ≠ jvmref
Proof step 28:
is_referencevalue(st[rk]), validrefnotnull(str, st[rk] .refval, ty, st), rk ∈ st, st ⊆ st1, rk ∈ st1 ⊦ st[rk] .refval = jvmref, validrefvalnotnull(str, st1[rk], ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st ∧ ¬ rk ∈ st0 → ¬ st ⊆ st0])]]