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Proof step 32 from proof validrefkeynotnull-subset (previous step)

st ⊆ st1, rk ∈ st ∧ validrefvalnotnull(str, st[rk], ty, st) ⊦ validrefkeynotnull(str, rk, ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 31:
validrefvalnotnull(str, st[rk], ty, st), rk ∈ st, st ⊆ st1 ⊦ validrefkeynotnull(str, rk, ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]