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Proof step 1 from proof validrefkeynotnull-union-01 (
previous step
)
⊦ validrefkeynotnull(str, rk, ty, st) ∧ (∃ st0. st1 = st0 ∪ st) → validrefkeynotnull(str, rk, ty, st1)
Lemma
validrefkeynotnull-union