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Proof step 27 from proof validrefkeynotnull-union (previous step)

is_referencevalue(st[rk]) ∧ validrefnotnull(str, st[rk] .refval, ty, st), rk ∈ st ⊦ rk ∈ st0 ∪ st ∧ validrefvalnotnull(str, (st0 ∪ st)[rk], ty, st0 ∪ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ validrefnotnull(str, r, ty, st) → r ≠ jvmref
Proof step 26:
is_referencevalue(st[rk]), validrefnotnull(str, st[rk] .refval, ty, st), rk ∈ st ⊦ st[rk] .refval = jvmref, validrefvalnotnull(str, st[rk], ty, st0 ∪ st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st0 → (st ∪ st0)[rk] = st0[rk]], [CSIMPSEQ : ⊦ rk ∈ st ∪ st0 ↔ rk ∈ st ∨ rk ∈ st0])]]