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Proof step 6 from proof validreflist-addarray (previous step)

newref(newref(st), st) ∧ validref(str, r, ty1, st), validreflist(str, vals1, ty1, st), validref(str, r, ty1, st), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ true ∧ validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
validreflist(str, vals1, ty1, st), validref(str, r, ty1, st), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ newref(newref(st), st)])]]