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Proof step 9 from proof validreflist-addarray (previous step)

validreflist(str, vals1, ty1, st), validref(str, r, ty1, st), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ validreflist(str, refval(r) ' + vals1, ty1, addarray(newref(st), ty, vals0, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ validreflist(str, val ' + vals, ty, st) ↔ is_referencevalue(val) ∧ validref(str, val .refval, ty, st) ∧ validreflist(str, vals, ty, st)
Proof step 8:
validreflist(str, vals1, ty1, st), validref(str, r, ty1, st), ∀ str, ty1, st, ty, vals0. validreflist(str, vals1, ty1, st) → validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st)) ⊦ is_referencevalue(refval(r)) ∧ validref(str, refval(r) .refval, ty1, addarray(newref(st), ty, vals0, st)) ∧ validreflist(str, vals1, ty1, addarray(newref(st), ty, vals0, st))

Rule argument

[crewrite-arg: validreflist-rec , F , [st, ty, vals, val, str] → [addarray(newref(st), ty, vals0, st), ty1, vals1, refval(r), str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addarray(newref(st), ty, vals0, st), ty1, vals1, refval(r), str)]]