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Proof step 2 from proof validreflist-one (conclusion)

⊦ validreflist(str, val ', ty, st) ↔ is_referencevalue(val) ∧ validref(str, val .refval, ty, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ validreflist(str, vals, ty, st) ↔ (∀ val. val ∈ vals → is_referencevalue(val) ∧ validref(str, val .refval, ty, st))

Rule argument

[crewrite-arg: validreflist-def , F , [st, ty, vals, str] → [st, ty, val ', str] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ val ∈ val0 ' ↔ val = val0])], [EXTRATERMS : (st, ty, val ', str)]]