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Proof step 9 from proof validreflist-rec (previous step)

validref(str, r, ty, st), ∀ val. val ∈ vals → is_referencevalue(val) ∧ validref(str, val .refval, ty, st), val0 = refval(r) ∨ val0 ∈ vals ⊦ is_referencevalue(val0) ∧ validref(str, val0 .refval, ty, st)

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 2, [extquanttermlist: (val0)abort:F, discard:F, computed:T]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))], [CSIMPSEQ : ⊦ refval(r) .refval = r])], [EXTRATERMS : (val0)]]