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Proof step 10 from proof validrefnotnull-subset (conclusion)

⊦ validrefnotnull(str, r, ty, st) ∧ st ⊆ st1 → validrefnotnull(str, r, ty, st1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ validrefnotnull(str, r, ty, st) → r ≠ jvmref
Proof step 9:
validrefnotnull(str, r, ty, st), st ⊆ st1 ⊦ r = jvmref, validrefnotnull(str, r, ty, st1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]