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Proof step 4 from proof validrefval-junkref (previous step)

junkref(str, val .refval, st), validrefval(str, val, ty, st) ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 1:
⊦ ¬ junkref(str, jvmref, st)
Proof step 2:
⊦ validrefval(str, refval(r), ty, st) ↔ validref(str, r, ty, st)
Proof step 3:
⊦ junkref(str, r, st) → ¬ validref(str, r, ty, st)

Rule argument

[speclemmaarg: is_referencevalue(val) ,r = val .refval ↔ val = refval(r) ,[val, r] → [val, r] ,T ,javavalue , ,elim-refval ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_referencevalue(val) → val .refval = jvmref], [CSIMPSEQ : ⊦ is_referencevalue(refval(r))], [CSIMPELIM : is_referencevalue(val) ⊦ r = val .refval ↔ val = refval(r)])], [EXTRATERMS : (val, r)]]