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Proof step 5 from proof validrefval-union (previous step)

val = refval(r), validref(str, r, ty, st), is_referencevalue(val) ⊦ validrefval(str, val, ty, st0 ∪ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ validrefval(str, refval(r), ty, st) ↔ validref(str, r, ty, st)
Proof step 4:
validref(str, r, ty, st) ⊦ validref(str, r, ty, st0 ∪ st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_referencevalue(refval(r))])]]