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Proof step 7 from proof validrefval-union (previous step)

is_referencevalue(val) ∧ validref(str, val .refval, ty, st) ⊦ validrefval(str, val, ty, st0 ∪ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
validref(str, val .refval, ty, st), is_referencevalue(val) ⊦ validrefval(str, val, ty, st0 ∪ st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]