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Proof step 14 from proof validstatfield-putrkvs (
previous step
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⊦ rk ∈ rkvs ↔ (∃ rkvs0, val, rkvs1. rkvs = rkvs0 + ((rk × val) + rkvs1) ∧ ¬ rk ∈ rkvs1)
A spec-lemma