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Proof step 13 from proof validstatfield-subset (conclusion)

⊦ validstatfield(str, sk, st) ∧ st ⊆ st0 ∧ initdone(sk .fs .class, st0) ∧ initdone(sk .fs .class, st) → validstatfield(str, sk, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
initdone(sk .fs .class, st), initdone(sk .fs .class, st0), st ⊆ st0, validstatfield(str, sk, st) ⊦ validstatfield(str, sk, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]