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Proof step 9 from proof validstatfields-rec (previous step)

⊦ (∀ sk0. sk0 = sk ∨ sk0 ∈ sks → validstatfield(str, sk0, st)) ↔ validstatfield(str, sk, st) ∧ (∀ sk. sk ∈ sks → validstatfield(str, sk, st))

User applied rule case distinction

And obtained the following new goals

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]