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Proof step 4 from proof validsubset-addclass-01 (conclusion)

⊦ valid⊆(str, st, st0) → valid⊆(str, st, addclass(class, fis, st0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
valid⊆(str, st, st0) ⊦ valid⊆(str, st, addclass(class, fis, st0))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]