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Proof step 2 from proof validsubset-okbytearray-01 (conclusion)
⊦ okbytearray(r, st) ∧ valid⊆(str, st, st0) → okbytearray(r, st0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 1
:
⊦ ¬ okbytearray(r, st0) ∧ valid⊆(str, st, st0) → ¬ okbytearray(r, st)
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]