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Proof step 5 from proof validsubset-validref-forward (conclusion)

⊦ valid⊆(str, st, st0) ∧ validref(str, r, ty, st) → validref(str, r, ty, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
validref(str, r, ty, st), valid⊆(str, st, st0) ⊦ validref(str, r, ty, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]