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Proof step 6 from proof validval-index-norefval (conclusion)

⊦ ¬ is_referencevalue(val) → (validval(str, r -- i ', val, st) ↔ okval(val, st[r -- _type] .type .type))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ validval(str, r -- i ', val, st) ↔ okval(val, st[r -- _type] .type .type), is_referencevalue(val)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]