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Proof step 125 from proof validval-put-any (previous step)

rk = r1 -- sk0, sk .fs = mkfs(class, ty, fieldvar), validval(str, rk, val, st), is_indexkey(sk), okval(refval(r0), st[r -- _type] .type .type), validref(str, r0, st[r -- _type] .type .type, st) ⊦ r -- _type = rk, validref(str, r0, st[r -- _type] .type .type, st[rk, val]), ( is_fskey(sk0) → (is_referencevalue(val) → validref(str, val .refval, sk0 .fs .type, st) ∧ is_reftype(sk0 .fs .type)) ∧ (¬ is_referencevalue(val) → okval(val, sk0 .fs .type) ∧ sk0 .fs .type ≠ void_type ∧ sk0 ≠ _length)) ∧ ( is_indexkey(sk0) → ( is_referencevalue(val) → validref(str, val .refval, st[r1 -- _type] .type .type, st) ∧ r1 ≠ jvmref ∧ is_arraytype(st[r1 -- _type] .type) ∧ (val .refval = jvmref → is_reftype(st[r1 -- _type] .type .type))) ∧ (¬ is_referencevalue(val) → okval(val, st[r1 -- _type] .type .type)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 124:
sk .fs = mkfs(class, ty, fieldvar), validval(str, r1 -- sk0, val, st), is_indexkey(sk), okval(refval(r0), st[r -- _type] .type .type), validref(str, r0, st[r -- _type] .type .type, st), r ≠ r1 ∨ _type ≠ sk0 ⊦ validref(str, r0, st[r -- _type] .type .type, st[r1 -- sk0, val]), ( is_fskey(sk0) → (is_referencevalue(val) → validref(str, val .refval, sk0 .fs .type, st) ∧ is_reftype(sk0 .fs .type)) ∧ (¬ is_referencevalue(val) → okval(val, sk0 .fs .type) ∧ sk0 .fs .type ≠ void_type ∧ sk0 ≠ _length)) ∧ ( is_indexkey(sk0) → ( is_referencevalue(val) → validref(str, val .refval, st[r1 -- _type] .type .type, st) ∧ r1 ≠ jvmref ∧ is_arraytype(st[r1 -- _type] .type) ∧ (val .refval = jvmref → is_reftype(st[r1 -- _type] .type .type))) ∧ (¬ is_referencevalue(val) → okval(val, st[r1 -- _type] .type .type)))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)])]]