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Proof step 86 from proof validval-put-any (previous step)

sk .fs = mkfs(class, ty, fieldvar), validval(str, r1 -- mkfs(class0, ty0, fieldvar0) ', val, st), is_indexkey(sk), okval(refval(r0), st[r -- _type] .type .type), validref(str, r0, st[r -- _type] .type .type, st), is_referencevalue(val), r ≠ r1 ∨ _type ≠ mkfs(class0, ty0, fieldvar0) ' ⊦ validref(str, r0, st[r -- _type] .type .type, st[r1 -- mkfs(class0, ty0, fieldvar0) ', val]), validref(str, val .refval, ty0, st) ∧ is_reftype(ty0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 85:
val = refval(r2), sk .fs = mkfs(class, ty, fieldvar), validval(str, r1 -- mkfs(class0, ty0, fieldvar0) ', val, st), is_indexkey(sk), okval(refval(r0), st[r -- _type] .type .type), validref(str, r0, st[r -- _type] .type .type, st), is_referencevalue(val), r ≠ r1 ∨ _type ≠ mkfs(class0, ty0, fieldvar0) ' ⊦ validref(str, r0, st[r -- _type] .type .type, st[r1 -- mkfs(class0, ty0, fieldvar0) ', val]), validref(str, r2, ty0, st) ∧ is_reftype(ty0)

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [val, r2] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (val, r2)]]