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Proof step 22 from proof validvals-append (previous step)

⊦ (∀ rkv. rkv ∈ rkvs ∨ rkv ∈ rkvs0 → validval(str, rkv .1, rkv .2, st)) ↔ validvals(str, rkvs, st) ∧ validvals(str, rkvs0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ validvals(str, rkvs, st) ↔ (∀ rkv. rkv ∈ rkvs → validval(str, rkv .1, rkv .2, st))
Proof step 21:
⊦ (∀ rkv. rkv ∈ rkvs ∨ rkv ∈ rkvs0 → validval(str, rkv .1, rkv .2, st)) ↔ (∀ rkv. rkv ∈ rkvs → validval(str, rkv .1, rkv .2, st)) ∧ validvals(str, rkvs0, st)

Rule argument

[crewrite-arg: validrefkeyvalues-def , F , [st, rkvs, str] → [st, rkvs, str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, rkvs, str)]]