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Proof step 2 from proof validvals-one (previous step)

⊦ validvals(str, (rk × val) ', st) ↔ validval(str, rk, val, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ validvals(str, rkvs, st) ↔ (∀ rkv. rkv ∈ rkvs → validval(str, rkv .1, rkv .2, st))

Rule argument

[crewrite-arg: validrefkeyvalues-def , F , [st, rkvs, str] → [st, (rk × val) ', str] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rkv ∈ rkv0 ' ↔ rkv = rkv0], [CSIMPSEQ : ⊦ (rk × val) .1 = rk], [CSIMPSEQ : ⊦ (rk × val) .2 = val])], [EXTRATERMS : (st, (rk × val) ', str)]]