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Proof step 7 from proof validvals-put-any (previous step)

validval(str, rk, val, st), validvals(str, rkvs, st), rk0 × val0 ∈ rkvs ⊦ validval(str, rk0, val0, st[rk, val])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ validvals(str, rkvs, st) ↔ (∀ rkv. rkv ∈ rkvs → validval(str, rkv .1, rkv .2, st))
Proof step 6:
validval(str, rk, val, st), ∀ rkv. rkv ∈ rkvs → validval(str, rkv .1, rkv .2, st), rk0 × val0 ∈ rkvs ⊦ validval(str, rk0, val0, st[rk, val])

Rule argument

[crewrite-arg: validrefkeyvalues-def , F , [st, rkvs, str] → [st, rkvs, str] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, rkvs, str)]]