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Proof step 4 from proof addarrays-at-other-01 (previous step)

r ∈ st ⊦ (addarrays(newref(st) ', ty, [], i, st)[r -- sk]) = st[r -- sk]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ints = [] ∨ n→i(# refs) ≠ countrefs(ints) ∨ ¬ posints(ints) → addarrays(refs, ty, ints, i, st) = st

Rule argument

[crewrite-arg: addarrays-empty , F , [st, i, ints, ty, refs] → [st, i, [], ty, newref(st) '] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, i, [], ty, newref(st) ')]]