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Proof step 49 from proof addarrays-at-other-01 (previous step)

ints ≠ [] ∧ n→i(# newref_list(i→n(countrefs(ints)), st)) = countrefs(ints) ∧ posints(ints), posints(ints), r ∈ st, i < 0 ⊦ (addmultiarrays(newref_list(i→n(countrefs(ints)), st), ints .first, [], mktype_from_dims(ty, countdims(ints, i)), getdims(ints), st)[r -- sk]) = st[r -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
⊦ abs(countrefs(ints)) = countrefs(ints)
Proof step 48:
posints(ints), r ∈ st, i < 0 ⊦ (addmultiarrays(newref_list(i→n(countrefs(ints)), st), ints .first, [], mktype_from_dims(ty, countdims(ints, i)), getdims(ints), st)[r -- sk]) = st[r -- sk], ints = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ n→i(i→n(i)) = abs(i)], [CSIMPSEQ : ⊦ # newref_list(n, st) = n])]]