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Proof step 50 from proof addarrays-auto-22 (conclusion)

⊦ addarrays(refs, ty, 2 ' + 2 ', 0, st) = ((# refs = 3 ⊃ addarray (refs .first, mkarraytype(ty), refval(refs .rest .first) ' + refval(refs[2]) ', addarray(refs[1], ty, 2, addarray(refs .rest .rest .first, ty, 2, st))) ; st ) )

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 42:
# refs = 3 ⊦ addarrays(refs, ty, 2 ' + 2 ', 0, st) = addarray (refs .first, mkarraytype(ty), refval(refs .rest .first) ' + refval(refs[2]) ', addarray(refs[1], ty, 2, addarray(refs .rest .rest .first, ty, 2, st)))
Proof step 49:
# refs ≠ 3 ⊦ addarrays(refs, ty, 2 ' + 2 ', 0, st) = st

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]