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Proof step 8 from proof addarrays-case (conclusion)

⊦ addarrays(refs, ty, ints, i, st) = (((ints ≠ [] ∧ n→i(# refs) = countrefs(ints) ∧ posints(ints)) ⊃ addmultiarrays(refs, ints .first, [], mktype_from_dims(ty, countdims(ints, i)), getdims(ints), st) ; st ) )

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 5:
ints ≠ [] ∧ n→i(# refs) = countrefs(ints) ∧ posints(ints) ⊦ addarrays(refs, ty, ints, i, st) = addmultiarrays(refs, ints .first, [], mktype_from_dims(ty, countdims(ints, i)), getdims(ints), st)
Proof step 7:
ints = [] ∨ n→i(# refs) ≠ countrefs(ints) ∨ ¬ posints(ints) ⊦ addarrays(refs, ty, ints, i, st) = st

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]