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Proof step 26 from proof addarrays-fieldin (previous step)

n→i(# refs) = countrefs(ints), is_fskey(sk), posints(ints) ⊦ ints = [], r -- sk ∈ addarrays(refs, ty, ints, i, st) ↔ r -- sk ∈ st, sk = _type, sk = _length

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ints ≠ [] ∧ n→i(# refs) = countrefs(ints) ∧ posints(ints) → addarrays(refs, ty, ints, i, st) = addmultiarrays(refs, ints .first, [], mktype_from_dims(ty, countdims(ints, i)), getdims(ints), st)
Proof step 25:
ints ≠ [] ∧ n→i(# refs) = countrefs(ints) ∧ posints(ints), n→i(# refs) = countrefs(ints), is_fskey(sk), posints(ints) ⊦ ints = [], r -- sk ∈ addmultiarrays(refs, ints .first, [], mktype_from_dims(ty, countdims(ints, i)), getdims(ints), st) ↔ r -- sk ∈ st, sk = _type, sk = _length

Rule argument

[crewrite-arg: addarrays-def , F , [st, i, ints, ty, refs] → [st, i, ints, ty, refs] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, i, ints, ty, refs)]]