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Proof step 26 from proof addarrays-out (previous step)

¬ (ints = [] ∨ n→i(# refs) ≠ countrefs(ints) ∨ ¬ posints(ints)) ⊦ (addarrays(refs, ty, ints, i, st)[_out]) = st[_out]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
n→i(# refs) = countrefs(ints), posints(ints) ⊦ ints = [], (addarrays(refs, ty, ints, i, st)[_out]) = st[_out]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]