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Proof step 18 from proof addarrays-subset (previous step)

rk ∈ st, is_newref_list(refs, st), 0 ≤ i ⊦ st[rk] = (addarrays(refs, ty, ints, i, st)[rk])

User applied rule structural induction

And obtained the following new goals

Proof step 17:
r -- sk ∈ st, is_newref_list(refs, st), 0 ≤ i ⊦ st[r -- sk] = (addarrays(refs, ty, ints, i, st)[r -- sk])

Rule argument

[VARWITHVARSEQSARG : rk, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : refkey generated by --;])]]