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Proof step 8 from proof countdims-zero-03 (conclusion)

⊦ 0 < i → countdims(ints, i) ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
countdims(ints, i) = 0, 0 < i ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j], [CSIMPFORWARD : ⊦ i < i0 ∧ i = i1 → i1 < i0])]]