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Proof step 22 from proof countrefs-getdims-01 (conclusion)

⊦ countrefs(i ' + getdims(ints)) = countrefs(i ' + ints)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ # ints ≤ 1 → countrefs(ints) = 1
Proof step 19:
¬ # (i ' + getdims(ints)) ≤ 1 ⊦ countrefs(i ' + getdims(ints)) = countrefs(i ' + ints)
Proof step 20:
⊦ getdims(ints) = [] ↔ ints = []
Proof step 21:
⊦ countrefs(i ') = 1

Rule argument

[crewrite-arg: countrefs-base, F, [ints] → [i ' + getdims(ints)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # (ints + ints0) = # ints + # ints0], [CSIMPSEQ : ⊦ # i ' = 0 +1], [CSIMPSEQ : ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1], [CSIMPSEQ : ⊦ m + n ≤ m ↔ n = 0], [CSIMPSEQ : ⊦ # ints = 0 ↔ ints = []], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ ints + [] = ints])], [EXTRATERMS : (i ' + getdims(ints))]]